0=5x^2-36x+55

Solution for 0=5x^2-36x+55 equation:

0=5x^2-36x+55

We move all terms to the left:

0-(5x^2-36x+55)=0

We add all the numbers together, and all the variables

-(5x^2-36x+55)=0

We get rid of parentheses

-5x^2+36x-55=0

a = -5; b = 36; c = -55;
Δ = b2-4ac
Δ = 362-4·(-5)·(-55)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-14}{2*-5}=\frac{-50}{-10}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+14}{2*-5}=\frac{-22}{-10}
=2+1/5
$